0.2x^2-0.06x+0.0045=0

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Solution for 0.2x^2-0.06x+0.0045=0 equation: 



0.2x^2-0.06x+0.0045=0

a = 0.2; b = -0.06; c = +0.0045;
Δ = b2-4ac
Δ = -0.062-4·0.2·0.0045
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0.06}{0.4}=0.06/0.4$

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